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x-4x^2=-28
We move all terms to the left:
x-4x^2-(-28)=0
We add all the numbers together, and all the variables
-4x^2+x+28=0
a = -4; b = 1; c = +28;
Δ = b2-4ac
Δ = 12-4·(-4)·28
Δ = 449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{449}}{2*-4}=\frac{-1-\sqrt{449}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{449}}{2*-4}=\frac{-1+\sqrt{449}}{-8} $
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